Author | Message | Time |
---|---|---|
LivedKrad | I'm having trouble following procedure for solving absolute value inequalities. e.g. | (( x + 5 ) / 3 ) | - 3 > 6 I proceded to set the inequality up as two inequalities.. (( x + 5) / 3 ) - 3 < -6 or (( x + 5) / 3 ) - 3 > 6 I then solved accordingly... (( x + 5) / 3 ) < -3 or (( x + 5) / 3 ) > 9 (x + 5) < -9 or (x + 5) > 27 x < -14 or x > 22 Yet, this is wrong! I can't seem to figure out what I did wrong. Help please :( | October 21, 2004, 11:05 PM |
LivedKrad | UPDATE: Solved. | October 21, 2004, 11:32 PM |
j0k3r | Generally when you have a problem and solve it, you post your solution so that others may learn from it. | October 22, 2004, 12:11 AM |
Yoni | You can't treat the -3 with such disrespect. First it has to blend in with the 6 in the RHS. | (( x + 5 ) / 3 ) | > 9 Now proceed normally... | October 22, 2004, 9:59 AM |