Author | Message | Time |
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Eibro | lim x->0- ( ( 1 / x ) - ( 1 / |x| ) ) I think it should be -infinity, since we have 1 / (a very large negative number) - 1 / ( a very large positive number ) yet my calculus book lists it as 0. Help! Mr. Calculus professor told us 1 / |x| could be evaluated to 1 / -x in the case where x -> 0-. That is how I deduced the above. | October 4, 2004, 2:20 AM |
Yoni | x -> 0-, therefore x is always negative. 1/x is a negative numer. 1/|x| is a positive number. Hence 1/x - 1/|x| is equal to 2/x, or a negative number that approaches -infinity. A miscommunication is between: 1. You and the book 2. You and the teacher 3. The book and the teacher 4. You and this forum Discover who is wrong and post back with more! | October 4, 2004, 3:50 AM |
Eibro | Oops. You're right. The calculus book lists it as undefined. So negative infinity seems to be the answer. | October 4, 2004, 7:38 PM |