Author | Message | Time |
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Gangz | K this time i am ahving 2 problems... after i figure these 2 out i pretty much got it figured out.. Unbannign with * script [code] Dim argSplit As Variant, temp As String argSplit = Split(message) If UCase(argSplit(0)) = Form1.varTrigger & "UNBAN" Then templen = Len(argSplit(0) & argSplit(1)) + 1: If templen <> Len(message) Then temp = Mid(message, templen + 1) If InStr(argSplit(1), "*") Then For X = 0 To Form1.cbobanned.ListCount - 1 If Form1.cbobanned.List(X) Like argSplit(1) Then Form1.cboQueue.AddItem "/unban " & Form1.cbobanned.List(X) & temp Next X Else: Form1.cboQueue.AddItem "/unban " & argSplit(1) & temp End If End If [/code] im not asking anyone to re-write i it to work just point out erros =\ And i also was wondering how to remove users from a userlist.. this is the adding code [code] If UCase(Mid(message, 1, 5)) = Form1.varTrigger & "ADD " Then Dim User As String User = (Mid(message, 6)) Form1.cboUsers.AddItem User[/code] i can add just not remove =\ because it adds the user with flags such as M O S B | February 7, 2004, 7:20 AM |
hismajesty | You have to use an API call to remove from a ListBox. I don't remember it off the top of my head though, try msdn. | February 7, 2004, 12:58 PM |
Newby | Use an array to store your users. :\ | February 7, 2004, 3:28 PM |
UserLoser. | [quote author=hismajesty link=board=17;threadid=5148;start=0#msg42944 date=1076158704] You have to use an API call to remove from a ListBox. I don't remember it off the top of my head though, try msdn. [/quote] Hmm.. [code]int i_Retval = SendMessage(lstHwnd, LB_FINDSTRING, 0, (LPARAM)"My listbox item"); SendMessage(lstHwnd, LB_DELETESTRING, i_Retval, 0);[/code] | February 7, 2004, 5:10 PM |
hismajesty | Yes, UserLoser, but I remember you giving me a direct API call for that a while back. Without having to use SendMessage. | February 8, 2004, 12:22 AM |
Gangz | Eh... I gatta look this one up =\.. its kinda complecated i can see | February 8, 2004, 6:22 AM |
UserLoser. | [quote author=Gangz link=board=17;threadid=5148;start=0#msg43082 date=1076221356] Eh... I gatta look this one up =\.. its kinda complecated i can see [/quote] There is a much simpiler way, something like: [code] Dim I as Long For I = 0 To MyList.ListCount If UCase(MyList.List(i)) = UCase(UserToRemove) Then MyList.RemoveItem I: Exit For Next I [/code] | February 8, 2004, 4:35 PM |
Gangz | [quote author=UserLoser. link=board=17;threadid=5148;start=0#msg43122 date=1076258159] [quote author=Gangz link=board=17;threadid=5148;start=0#msg43082 date=1076221356] Eh... I gatta look this one up =\.. its kinda complecated i can see [/quote] There is a much simpiler way, something like: [code] Dim I as Long For I = 0 To MyList.ListCount If UCase(MyList.List(i)) = UCase(UserToRemove) Then MyList.RemoveItem I: Exit For Next I [/code] [/quote] wont work.. that is were i get caught up to... On the list it adds as Userloser. M ... So i need it to remove the whole line =\ | February 8, 2004, 7:05 PM |
UserLoser. | [quote author=Gangz link=board=17;threadid=5148;start=0#msg43142 date=1076267104] [quote author=UserLoser. link=board=17;threadid=5148;start=0#msg43122 date=1076258159] [quote author=Gangz link=board=17;threadid=5148;start=0#msg43082 date=1076221356] Eh... I gatta look this one up =\.. its kinda complecated i can see [/quote] There is a much simpiler way, something like: [code] Dim I as Long For I = 0 To MyList.ListCount If UCase(MyList.List(i)) = UCase(UserToRemove) Then MyList.RemoveItem I: Exit For Next I [/code] [/quote] wont work.. that is were i get caught up to... On the list it adds as Userloser. M ... So i need it to remove the whole line =\ [/quote] Try: [code] Dim I as Long Dim Sp() as String For I = 0 To MyList.ListCount Sp() = Split(MyList.List(I), " ") If UCase(Sp(0)) = UCase(UserToRemove) Then MyList.RemoveItem I: Exit For Next I [/code] Sp(0) would be Userloser. Sp(1) would be M | February 8, 2004, 10:32 PM |
Newby | I was going to say that. But then I got lazy and fell asleep :( | February 8, 2004, 11:10 PM |
Networks | Public Function WildCard(ByVal WC As String, ByVal SearchStr As String) As Boolean If WC Like SearchStr Then WildCard = True Exit Function Else WildCard = False End If End Function Could someone give me a usage for when someone joins the channel and meets specifications for a wildcard ban? | February 9, 2004, 7:13 PM |
Myndfyr | okay, first use [ code ] [ /code ] tags: [code] Public Function WildCard(ByVal WC As String, ByVal SearchStr As String) As Boolean If WC Like SearchStr Then WildCard = True Exit Function Else WildCard = False End If End Function [/code] And here is some Pseudocode for you: [code] ' Assume that mySrchStr is declared as a String variable ' Sorry, this code looks like Visual Basic 7.... You should be able to ' get the meaning out of it though, hence _pseudo_code... Public Function User_Joined (ByVal usr As String, ByVal flags As Integer, ByVal stats As String, ByVal ping As Integer) Handles Me.connection.UserJoined If WildCard mySrchStr, usr DoMyWildcardAction End If End Function[/code] | February 9, 2004, 7:52 PM |
o.OV | [code] Public Function WildCard(ByVal WC As String, ByVal SearchStr As String) As Boolean If WC Like SearchStr Then WildCard = True Exit Function Else WildCard = False End If End Function [/code] er.. it should look something like this.. [code] Public Function WildCard(ByVal WC As String, ByVal SearchStr As String) As Boolean wildcard = (WC Like SearchStr) End Function [/code] Why would you want to even bother making such a simple function.. the Like operator returns a boolean value already... | February 10, 2004, 2:57 AM |
Myndfyr | [quote author=o.OV link=board=17;threadid=5148;start=0#msg43433 date=1076381860] Why would you want to even bother making such a simple function.. the Like operator returns a boolean value already... [/quote] I disagree. What happens when somewhere down the line, he wants to change his wildcard processing? This is good encapsulation (although I doubt he knew that). | February 10, 2004, 4:03 AM |
Soul Taker | Yes, would be a good idea to make a function for wildcard matching which changes the default behavior of some masking characters. | February 10, 2004, 4:29 AM |
Networks | I dont want a function I want a usage for ID_JOIN and ID_TALK please? Assume i have a channellist if you must. | February 10, 2004, 1:59 PM |
o.OV | [quote author=Soul Taker link=board=17;threadid=5148;start=0#msg43467 date=1076387375] Yes, would be a good idea to make a function for wildcard matching which changes the default behavior of some masking characters. [/quote] Good point. that reminds me.. [code] leftFlat = "[" ChrW1 = ChrW$(1) TempA = MainStr Position = InStr(TempA, leftFlat) If Position Then For X = 0 To 255 Mid$(TempA, Position, 1) = Chr1 Position = InStr(TempA, leftFlat) If Position = 0 Then Exit For Next X End If 'TempA is to be used with the Like operator in place _ of MainStr 'Same should be done for the other one.. [/code] That should keep the flat brackets from causing problems. | February 10, 2004, 3:53 PM |
o.OV | [quote author=Networks link=board=17;threadid=5148;start=15#msg43496 date=1076421543] I dont want a function I want a usage for ID_JOIN and ID_TALK please? Assume i have a channellist if you must. [/quote] So you plucked the code off of someone and you can't figure out how it works? Google, Google, and Google? | February 10, 2004, 4:04 PM |
Myndfyr | [quote author=Networks link=board=17;threadid=5148;start=15#msg43496 date=1076421543] I dont want a function I want a usage for ID_JOIN and ID_TALK please? Assume i have a channellist if you must. [/quote] Pseudocode: [code] Switch (EventID) Case ID_JOIN: If MatchesWildcard(Username, SEARCHSTRING) Then BanUser Username Else ChannelList.Add User WriteUserJoinedMessage User, Product End If End Case Case ID_TALK: If MatchesWildcard(Username, SEARCHSTRING) Then BanUser Username Else WriteUserSpokeMessage User, Message End If End Case End Switch [/code] Wow..... That was hard.... You should almost be able to move that right into VB by changing the Switch statement and replacing the Write...Message subroutine identifiers... (Excuse my VB grammar, I'm not sure how the Select...Case operator works.... I know that in C and its derivitives, we use case case:... break) | February 10, 2004, 4:14 PM |
Networks | I need some help with wildcarding code: I want to be abled to ban tags like: *]ZeR0[* in that format for example my wildcard function is: [code] Public Function matches(ByVal uName As String, ByVal Check As String) As Boolean Call PrepareCheck(Check) If uName = Empty Then matches = False Exit Function End If If LCase$(uName) Like LCase$(Check) Then matches = True End Function Function PrepareCheck(ByVal toCheck As String) As String toCheck = Replace(toCheck, "[", "ÿ") toCheck = Replace(toCheck, "]", "Ö") toCheck = Replace(toCheck, "~", "Ü") toCheck = Replace(toCheck, "#", "¢") toCheck = Replace(toCheck, "-", "£") toCheck = Replace(toCheck, "&", "¥") toCheck = Replace(toCheck, "@", "¤") toCheck = Replace(toCheck, "{", "ƒ") toCheck = Replace(toCheck, "}", "á") toCheck = Replace(toCheck, "^", "í") toCheck = Replace(toCheck, "`", "ó") toCheck = Replace(toCheck, "_", "ú") toCheck = Replace(toCheck, "+", "ñ") toCheck = Replace(toCheck, "$", "Ñ") PrepareCheck = LCase(toCheck) End Function [/code] I tested the function and it works fairly well except it wont find matches with *]ZeR0[* even when there is one: [code] For II = 1 To Form1.Users.ListItems.Count If matches(Form1.Users.ListItems(II), "*]zer0[") = True Then AddC vbGreen, Form1.Users.ListItems(II) & " was found." End If Next II [/code] it told me invalid pattern string y is this? Can someone please help me with wildcard code that can find matches w/ *]ZeR0[* please | February 12, 2004, 11:03 PM |
Myndfyr | Here is your code: [code] For II = 1 To Form1.Users.ListItems.Count If matches(Form1.Users.ListItems(II), "*]zer0[") = True Then AddC vbGreen, Form1.Users.ListItems(II) & " was found." End If Next II [/code] And let me highlight an interesting section: [font=courier] If matches(Form1.Users.ListItems(II), "*]zer0[" ) = True Then [/font] Forgot a * there smart guy. | February 12, 2004, 11:41 PM |
Networks | Not really cuz when its: *]ZeR0[ it says invalid pattern and if its *]zer0[* doesn't find it... Plus i have a user w/ a ]zer0[ tag in users Smart guy.... | February 12, 2004, 11:44 PM |