Valhalla Legends Forums Archive | General Discussion | Earth splash into Sun

AuthorMessageTime
iago
There will always be people complaing; I vote we just detonate an explosion in such a way that it will send the earth hurdling into the sun. That's the only way to shut everybody up.
September 10, 2003, 9:51 PM
Adron
[quote author=iago link=board=2;threadid=2621;start=15#msg20824 date=1063230697]
There will always be people complaing; I vote we just detonate an explosion in such a way that it will send the earth hurdling into the sun. That's the only way to shut everybody up.
[/quote]

That's a great idea. It would finally end all suffering and bring peace to the world. Who wouldn't want that?
September 10, 2003, 10:44 PM
Grok
[quote author=Adron link=board=2;threadid=2621;start=15#msg20836 date=1063233850]
[quote author=iago link=board=2;threadid=2621;start=15#msg20824 date=1063230697]
There will always be people complaing; I vote we just detonate an explosion in such a way that it will send the earth hurdling into the sun. That's the only way to shut everybody up.
[/quote]

That's a great idea. It would finally end all suffering and bring peace to the world. Who wouldn't want that?
[/quote]

Sounds good to me, let's start a new project.

I'm skeptical whether we can generate sufficient force to cause the Earth to fall into the Sun within our lifetimes.

Any of you physics/calculus people know the mass of the earth, it's angular velocity, trajectory, etc, and the formulae necessary to calculate a sufficient force to cause us to change orbit enough to hit the sun within 40 years?
September 10, 2003, 10:50 PM
Soul Taker
Sounds like the explosion itself would probably kill us before we hit the sun.
September 10, 2003, 11:43 PM
iago
[quote author=Grok link=board=2;threadid=2621;start=15#msg20840 date=1063234248]
[quote author=Adron link=board=2;threadid=2621;start=15#msg20836 date=1063233850]
[quote author=iago link=board=2;threadid=2621;start=15#msg20824 date=1063230697]
There will always be people complaing; I vote we just detonate an explosion in such a way that it will send the earth hurdling into the sun. That's the only way to shut everybody up.
[/quote]

That's a great idea. It would finally end all suffering and bring peace to the world. Who wouldn't want that?
[/quote]
I'm skeptical whether we can generate sufficient force to cause the Earth to fall into the Sun within our lifetimes.
[/quote]

Well, I'm 20, and I can expect to live till about 70, so let's aim for about 51 years :)
September 11, 2003, 12:28 AM
Adron
How much energy do we need? Is it similar to the earth's kinetic energy?
September 11, 2003, 4:55 PM
iago
Well, I heard somewhere that the earth weighs 6 terragrams, which would be 6000 gigagrams, 6,000,000 kilograms, or 6 billion grams. Correct me if I'm wrong there :)

Since the formula is F=ma, to get reasonable acceleration (let's say, 1000 (km/h)/s) we would have to put 1000 * 3.6 = 3600m/s^2 accelleration onto it, so the necessary force would be 3600 * 6,000,000,000,000 or 21,600,000,000,000,000J of force on it. Good luck! :-)
September 11, 2003, 5:14 PM
EvilCheese
A small antimatter explosion in the path of the planet should do it.

Or we could always vent the warp plasma. That normally works. :P
September 11, 2003, 5:44 PM
Adron
[quote author=iago link=board=2;threadid=2621;start=15#msg20920 date=1063300445]
Well, I heard somewhere that the earth weighs 6 terragrams, which would be 6000 gigagrams, 6,000,000 kilograms, or 6 billion grams. Correct me if I'm wrong there :)

Since the formula is F=ma, to get reasonable acceleration (let's say, 1000 (km/h)/s) we would have to put 1000 * 3.6 = 3600m/s^2 accelleration onto it, so the necessary force would be 3600 * 6,000,000,000,000 or 21,600,000,000,000,000J of force on it. Good luck! :-)
[/quote]

Try calculating the kinetic energy of earth instead and see if we want to land it over a period over 50 years what power input we need to feed it.
September 11, 2003, 8:02 PM
j0k3r
Note: We will burn up far before we actually hit the sun...

I say we make solar powered jetpacks and attach it to the back of the earth, so the closer we get the more power we get! Thereby eliminating some of our suffering...

Or we can slowly push the earth closer with small explosions over a couple years.
September 11, 2003, 8:28 PM
Grok
[quote author=Adron link=board=2;threadid=2621;start=15#msg20917 date=1063299337]
How much energy do we need? Is it similar to the earth's kinetic energy?
[/quote]

Some portion of it. Remember the gravitational acceleration will play a factor in helping us along. We just need a powerful enough nudge to slow down.

I'd think we merely have to slowing down some so that our "falling" towards the sun isn't equalled by our perpendicular kinetic energy.

Are we on the right track?
September 11, 2003, 8:41 PM
Grok
Some algorithms to start us on our journey to the sun.

http://www.edu-observatory.org/eo/algorithms.html

http://www.xylem.f2s.com/kepler/

http://ssd.jpl.nasa.gov/eph_info.html

Our position on a given day( the Earth-sun "ephemeris"):
http://ssd.jpl.nasa.gov/cgi-bin/eph

http://www.fourmilab.ch/cgi-bin/uncgi/Solar

Remember, I don't have the math knowledge to do this.
September 11, 2003, 8:49 PM
Soul Taker
[quote author=j0k3r link=board=2;threadid=2621;start=15#msg20932 date=1063312101]
Note: We will burn up far before we actually hit the sun...

I say we make solar powered jetpacks and attach it to the back of the earth, so the closer we get the more power we get! Thereby eliminating some of our suffering...

Or we can slowly push the earth closer with small explosions over a couple years.
[/quote]
May wish to note that the earth rotates every day, so the 'back' of it is not the back for long!
September 11, 2003, 9:11 PM
Hitmen
Let's hope no might-be terrorists read this. You could be giving them ideas!
September 11, 2003, 9:47 PM
iago
Terrorists want to get their point across.. if everybody was dead, there would be nobody to say, "Damn, we should have listened to their demands!"
September 11, 2003, 10:35 PM
Grok
Some responses on sci.physics newsgroup:

---------------------------------------
The kinetic energy of the earth in its motion about the sun is roughly
9*10^26 Joules. So that much work would have to be done on the Earth to
bring its orbital motion to zero.

Bob Kolker
---------------------------------------
Actually, it is more like 3*10^33 Joules.

So that much work would have to be done on the Earth to
>bring its orbital motion to zero.

The energy requirements are still the small part of it. Momentum
needs to be conserved as well. The linear momentum of the Earth, at
any given moment, is close to 2*10^29 Ns. Now, the Saturn V first
stage engine (or, rather, cluster of engines) had thrust of about
4*10^7 Ns. So, if you would build about a million of this babies
(never mind where the materials and labor are coming from), they would
have to run continuously for the next 150 million years (consuming an
amount of fuel 10 times larger than the Earth mass) to supply the
required impulse.

Mati Meron
---------------------------------------
Let's see. It's been a long time I played with planet but...

I think Uncle Al that if you just stop the motion of the earth it's
total mechanical energy E will still be negative, E<0 , due to just
the potential of the sun and it will again attain an elliptical orbit
around the sun but with some other radius and we will fry anyway.

It seems to me that in order to achieve what is called a "collision
path" or singular solution to orbit equations, one must increase the
total mechanical energy of the earth until it becomes E > 0. Then
earth will go into an open orbit (hyperbola or parabola) and depending
on eccentricity, mean and ecccentric anomaly, you may achieve a
collision course.

Contrary to common sense, of mayne not, the only way to increase the
total mechanical energy of the earth is by increasing its velocity.
Then bingo, 7 Bil morons fry to their extinction and the universe is
safe. Slowing it down does not do the job it seems, unless you also
supply an impulse to increase the total mechanical energy to positive
number.
---------------------------------------

Nope. It will be in a degenerate straight-line orbit
intersecting the Sun.

Hey, when you drop something on the Earth, does it go into
an elliptical orbit instead of hitting the ground?

---------------------------------------

KISS - keep it simple, stupid. Stop the Earth dead in its orbit, let
the sun do the rest of the work work, and get a default perfect hit in
the bargain (less Lens-Thirring frame dragging just before
touchdown). Note the prior post regarding crush strength of the
Earth.

The original poster has not calculated corrected time to splatter nor
velocity at hit,

http://www.math.ubc.ca/~israel/m215/falling2/falling2.html

suggesting it was just noise not inquiry.

Uncle Al
---------------------------------------

Depends on how close you are to the spheroid, dipshit.

---------------------------------------

No it does not. Stuff with zero orbital velocity falls straight down
vs. the fixed stars from any arbitrary height (ignoring wind) If you
look locally you subtract out ground motion and allow for ~1 cm/sec
horizontal Coriolus acceleration varying with latitude.

---------------------------------------

That's correct and I guess unless one is specific and uses the right
terms, like Uncle AL does, misunderstandings can arise.

The key word here is "fixed stars". If the answer is posed in this
context it's correct. However, in my answer I assumed an instantenuous
relative fix of earth's velocity with respect to a moving sun. This
case is a bit more complicated. Actually, everything is in a constant
relative motion and fixing anything could be hard. This is also one of
the reasons that in practice there is no such a thing as a "straight
line path" and what one perceives as a straight line in a free fall is
actually an arc of some curve.

This is to say, for those with a little hearing problem, that is there
is accelative motion the free falling planet towards the sun will also
attain a non-zero orbital velocity. This automatically activates conic
sections as the solutions and it's not a degenerate line orbit any
longer.

Have an idea: let's try it.
---------------------------------------

Mass of Earth is 5.976 * 10^24 kg.
50 years = 50 * 365.2422 * 86400 seconds = 1577846304 seconds
Velocity of Earth is 30 km/s.
Momentum of Earth is 30,000 m/s * 5.976 * 10^24 kg = 1.793 * 10^29 kg-m/s.

Force = momentum/duration = 1.793 * 10^29 kg-m/s / 1577846304 s
= 1.136 * 10^20 Newtons.

How one generates that force is an interesting issue. I don't know
what your budget is. :-)

---------------------------------------
All you have to do is change the orbit, by timing the
thrusts, to a highly elliptical one (think "comet") with
a closest approach that is within the sun's "atmosphere".
I'm assuming your customer would accept any form of
total fiery destruction, and doesn't require you to
actually plunge into the center of the sun.

- Randy
---------------------------------------
---------------------------------------
September 18, 2003, 2:46 PM
j0k3r
Something that I thought of while reading this post... What's the energy of a nuclear bomb and how much do we know about it's effect on our planet's course around the sun? Clearly it has tremendous energy, is it possible that this might have thrown us off course very slightly?

All this does not need to be done at once I am sure. We could slowly use up the energy as we get it to slow the Earth/push it...
September 18, 2003, 8:28 PM
Hitmen
I belive the energy of a nuclear weapon is far too little to throw the earth off course even the slightest bit.
September 18, 2003, 8:31 PM
iago
E=mc^2.. just figure out the mass of whatever is reacting :)
September 18, 2003, 9:46 PM
Camel
If one were to take the energy released by an atomic bomb, and spread it out so the blast range covored the entire volume of the earth, the concentration of energy would significantly decrease. If you're worried about the Earth being thrown off course, consider that the gravitational pull of another planet/comet/etc will have a much more dramatic affect on Earth's acceleration and will last for a much longer period of time. Then you will see that it is not the spoon that bends, it is only yourself.
September 19, 2003, 12:08 AM
Adron
Very interesting! So you don't think we'll be able to blow ourselves into the sun even if we turn all the water on earth into a hydrogen bomb?
September 19, 2003, 12:16 AM
Camel
[quote author=Adron link=board=2;threadid=2742;start=15#msg21635 date=1063930606]Very interesting! So you don't think we'll be able to blow ourselves into the sun even if we turn all the water on earth into a hydrogen bomb?[/quote]
I was talking about a few hundred atoms, not all of our oceans. Then again, there isn't as much water as you might think on Earth: While the majority of Earth's surface is obscured by water, the depth is rarely more than a couple of miles. It probably would be enough energy to significantly alter the velocity of the Earth, and certainly would be enough to wipe out virtually all life. Furthermore, there is a theory that if enough nuclear reactions occur in close proximity, they can covor the activation energy of a nuclear reaction. This means that there's a good chanse you could completely nuke the entire Earth and possibly more.
September 19, 2003, 12:34 AM
iago
[quote author=Camel link=board=2;threadid=2742;start=15#msg21633 date=1063930130]
If one were to take the energy released by an atomic bomb, and spread it out so the blast range covored the entire volume of the earth, the concentration of energy would significantly decrease. If you're worried about the Earth being thrown off course, consider that the gravitational pull of another planet/comet/etc will have a much more dramatic affect on Earth's acceleration and will last for a much longer period of time. Then you will see that it is not the spoon that bends, it is only yourself.
[/quote]

It doesn't matter where you do it, as long as you can change the momentum of the earth. It can be in one spot, as long as you can change the momentum.
September 19, 2003, 1:55 AM
Grok
[quote author=iago link=board=2;threadid=2742;start=15#msg21645 date=1063936518]It doesn't matter where you do it, as long as you can change the momentum of the earth. It can be in one spot, as long as you can change the momentum.[/quote]

Yes, Iago. It seems so simple. Any reduction of the Earth's orbital velocity should be enough. Remember that the Earth is always falling into the Sun. Currently the rate it is falling is offset by its orbital velocity. The falling is caused by gravity and the orbital velocity measures its momentum. Remove or reduce the momentum and the Earth's falling overtakes the balance, and it appears to "start falling" into the Sun.
September 19, 2003, 2:52 AM
Thing
It might be easier to make an impact on the moon that would cause the earth to change orbit.
September 19, 2003, 3:13 AM
Grok
[quote author=Thing link=board=2;threadid=2742;start=15#msg21657 date=1063941195]
It might be easier to make an impact on the moon that would cause the earth to change orbit.
[/quote]

Hmm, I don't see how exerting the force on the moon to cause the effect would need less energy. Whether the force is applied directly to the Earth, or via proxy through the moon, the actual force required would be the same.
September 19, 2003, 3:21 AM
iago
Well, if the moon's orbit was changed it would be consistantly putting a force on the earth because of the changed orbit, but if you did it to the earth it would only be changed by the initial force.. although Grok might be right, it's an interesting question :)
September 19, 2003, 3:29 AM
Adron
[quote author=iago link=board=2;threadid=2742;start=15#msg21662 date=1063942147]
Well, if the moon's orbit was changed it would be consistantly putting a force on the earth because of the changed orbit, but if you did it to the earth it would only be changed by the initial force.. although Grok might be right, it's an interesting question :)
[/quote]

Shouldn't the energy required to change it be constant no matter where we apply it? We may be able to save energy by picking a clever elliptical orbit that touches the sun instead of going for a straight hit though.
September 19, 2003, 12:04 PM
iago
Well, it seems like it should be comparable to pushing a ball on a flat surface or down an incline. You're providing the same force, but in one situation the force ends up with a sustained force... again, this could be wrong, though
September 19, 2003, 1:43 PM
Adron
[quote author=iago link=board=2;threadid=2742;start=15#msg21700 date=1063979028]
Well, it seems like it should be comparable to pushing a ball on a flat surface or down an incline. You're providing the same force, but in one situation the force ends up with a sustained force... again, this could be wrong, though
[/quote]

Hmm, to me that sounds more like the choice of what path to have the earth follow - linear approach or some kind of spiral. Just applying a certain force to the moon should move the moon a bit, but what you in reality are moving is the center of gravity of the system consisting of the moon and the earth. You'll change the orbits in which the moon and the earth rotate around each other, and whether you choose to move the moon or the earth I think you'll have the same effect on the center of gravity of the system.
September 19, 2003, 1:54 PM
Grok
Right. Think of the Earth and Moon as a closed mass-energy system. Doesn't matter which object in the system you apply the energy to, as the effect will be the same amount of energy.

The incline example: even without a push, the ball would still go down the incline. The force of your push adds a finite energy amount to the ball system.

Drop a pencil. Notice it falls to the floor. The only reason something orbits instead of falls is its angular velocity keeps it going away from the Earth at the same speed it is falling. But orbiting things ARE falling.

So again, all we have to do is reduce angular velocity by any amount, and the falling overtakes the going-away speed.
September 19, 2003, 3:13 PM
Camel
[quote author=Grok link=board=2;threadid=2742;start=30#msg21704 date=1063984424]So again, all we have to do is reduce angular velocity by any amount, and the falling overtakes the going-away speed.[/quote]
Would it not simply establish a new equilibrium, closer to the sun?

I was bored in my Calculus class today, and decided to write a simulator for this on my TI-83+. The numbers are completely wrong because I was just trying to get it to work correctly before inputting the actual data (which I didn't know at the time):

I've added whitespace and comments here for convenience

prgmSUN
[code]:ClrDraw

:3->O //number of objects. each matrix row is one object; format is {X, Y, Vx, Vy, Mass}
:[
[0,0, 0, 0, 0, 100]
[1,0, 0, 0, 0.1, 1]
[1.01,0, 0, 0.6, 1/6]
]->[J]

//This will set up the window to display everything correctly; it's not essential
:1->Ymax
:-1->Ymin
:94/62->Xmax
:-94/62->Xmin
:AxesOff
:FnOff
//to be completely explicit, one might also use PlotsOff, et al.

:Lbl L //i had to many [if:then:..:end]s, and decided i would just use Goto. much easier to read

//begin the draw loop. will draw a line for each object's velocity (it "points" backwards so that the line will look continuous)
:For(I,1,O
:[J](I,1)->X //displacement
:[J](I,2)->Y
:[J](I,5)->M //mass
:[J](I,3)*M->S //velocity
:[J](I,4)*M->T
:X+S->X // move to new position
:Y+T->Y
:X->[J](I,1 //store new position
:Y->[J](I,2
:Pt-On(X,Y
:Line(X,Y,X-S,Y-T //in writing this, i realize i should have stored the new position in different variables
:End

:For(I,1,O
:For(J,1,0
:If I != J:prgmSUNIJ //SUNIJ sounded really cool
:End
:End

:Goto L
[/code]

prgmSUNIJ
[code]
:[J](J,1)-[J](I,1)->X
:[J](J,2)-[J](I,2)->Y
:RtoPT(X,Y)->&#920; //under 'ANGLE', 6
:RtoPr(X,Y)->D //under 'ANGLE', 5

:[J](I,5)/De-4->A

:[J](J,3)->X
:[J](J,4)->Y
:X-Acos(&#920;)->X
:Y-Asin(&#920;)->Y
:X->[J](J,3
:Y->[J](J,4
[/code]
September 19, 2003, 8:19 PM
Grok
[quote author=Camel link=board=2;threadid=2742;start=30#msg21714 date=1064002779]
[quote author=Grok link=board=2;threadid=2742;start=30#msg21704 date=1063984424]So again, all we have to do is reduce angular velocity by any amount, and the falling overtakes the going-away speed.[/quote]
Would it not simply establish a new equilibrium, closer to the sun?[/quote]

Hold an object out away from your body. Drop it.

Did it go into low earth orbit at a reduced equilibrium? Why not? Why do you expect the Earth to go into a lower orbit around the Sun when you reduce the Earth's angular velocity?
September 19, 2003, 9:42 PM
Camel
[quote author=Grok link=board=2;threadid=2742;start=30#msg21722 date=1064007732]Hold an object out away from your body. Drop it.

Did it go into low earth orbit at a reduced equilibrium? Why not? Why do you expect the Earth to go into a lower orbit around the Sun when you reduce the Earth's angular velocity?[/quote]

If it has an angular velocity of zero it will reach equilibrium at the center of the earth, which it cannot reach because the path is obstructed. The question was about a scenario with reduced velocity, no zero velocity.

Perhaps I should rephrase my question: What is the relationship between the angular velocity required to keep Earth orbiting around the sun and the distance between them? If it requires less velocity as it gets closer, wouldn't the Earth simply establish a new equilibrium with its new velocity?
September 19, 2003, 10:37 PM
St0rm.iD
Perhaps we should instead have the moon crash into the earth. Since it has much less mass than the earth, it would be easier to do so. I also believe that a moon impact would have sufficient power to kill everyone.
September 20, 2003, 12:15 AM

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