Author | Message | Time |
---|---|---|
DDA-TriCk-E | I need to get the second digit of an int? e.g. int number = 4321; therefore i would need to get 3 Thanks. | September 19, 2007, 12:48 PM |
HdxBmx27 | Theres a couple ways you can do this, both are kinda eww. But 1) Convert it to a string and then use .charAt(1); Or 2) / x % 10, where X is 1 less signifigance then the int (If it was 1000, x = 100, num = 100, x=10, etc..) ~Hdx | September 19, 2007, 2:09 PM |
Yegg | The second method is probably the better way to go. | September 19, 2007, 4:03 PM |
DDA-TriCk-E | Thanks, didn't think about using the remainder operator. | September 19, 2007, 4:41 PM |
DDA-TriCk-E | Hmm, I actually need to get the second number ONLY, not the trailing numbers as well. Any ideas? I don't want to convert it to a String that looks too inefficient. | September 19, 2007, 4:47 PM |
HdxBmx27 | x = 123456; d = 10000; x/d = 12 12 % 10 = 2 what don't you get? ~Hdx | September 19, 2007, 4:50 PM |
DDA-TriCk-E | Ahh, sorry didn't read that properly... Thanks, got it working now :) | September 19, 2007, 4:54 PM |
Camel | [quote author=Hdx link=topic=17030.msg172933#msg172933 date=1190220629] x = 123456; d = 10000; x/d = 12 12 % 10 = 2 what don't you get? ~Hdx [/quote] d = Math.pow(10, Math.floor(Math.log(x)/Math.log(10))); would be more precise | September 19, 2007, 5:51 PM |