Author | Message | Time |
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Final | I have always wonderd how do you make a function with an unset amount of arguements its just been bothering me for a while can someone explain or point me to the way. Here what im wondering about. Regular function set arguements. void reg(int arg1,int arg2); Unset void uns(what goes in here); Utilization uns(25,26); // A c++ function that uses unset arguement number I THINK. sprintf () sprintf (buffer,"%s..ect",argument ,argument argument ,argument ...ect); | October 12, 2006, 5:32 AM |
K | Here's how it works. [code] // declare the function: void printf(const char* format, ...); [/code] at the beginning of the function: [code] va_list pa; va_start (pa, format); // start the var args pointer at the first argument. [/code] when you need to read another argument: [code] // to read the next argument, call va_arg with the var args ptr and the type of the next argument. uint32_t next_arg = va_arg(pa, uint32_t); [/code] when you're done: [code]va_end(pa); [/code] hope this helps. | October 12, 2006, 7:50 AM |
Rule | This tutorial may help: http://www.cprogramming.com/tutorial/c/lesson17.html | October 13, 2006, 1:51 AM |
Final | Awsome guys thanks again. Im going to play around with it see if i can make something usefull lol. | October 13, 2006, 5:25 AM |