Hello. I've come across a rather interesting problem involving float to int conversions. If I have a float, say, 98.85, and I assign an int to this float times 100...
[code]
float myfloat = 98.85;
int myint = myfloat * 100;
[/code]
myint becomes 9884, which is not what I want. Is there anyway to do this float->int conversion without losing precision and without making myint a float? I've figured a rather hack-like workaround by simply adding one to myint, but I would much rather a solution which did not involve this step.
Thanks.

Floats are weird in C++.  Your '98.85' is actually '98.849999...'  Adding 0.01 and then multiplying should work.

[quote author=sixb0nes link=topic=14770.msg150578#msg150578 date=1144971913]
Hello. I've come across a rather interesting problem involving float to int conversions. If I have a float, say, 98.85, and I assign an int to this float times 100...
[code]
float myfloat = 98.85;
int myint = myfloat * 100;
[/code]
myint becomes 9884, which is not what I want. Is there anyway to do this float->int conversion without losing precision and without making myint a float? I've figured a rather hack-like workaround by simply adding one to myint, but I would much rather a solution which did not involve this step.
Thanks.
[/quote]

Try this...
[code]
float myfloat = 98.85f;
int myint = (int)myfloat * 100;
[/code]

[quote author=Maddox link=topic=14770.msg150640#msg150640 date=1145140980]
[quote author=sixb0nes link=topic=14770.msg150578#msg150578 date=1144971913]
Hello. I've come across a rather interesting problem involving float to int conversions. If I have a float, say, 98.85, and I assign an int to this float times 100...
[code]
float myfloat = 98.85;
int myint = myfloat * 100;
[/code]
myint becomes 9884, which is not what I want. Is there anyway to do this float->int conversion without losing precision and without making myint a float? I've figured a rather hack-like workaround by simply adding one to myint, but I would much rather a solution which did not involve this step.
Thanks.
[/quote]

Try this...
[code]
float myfloat = 98.85f;
int myint = (int)myfloat * 100;
[/code]
[/quote]

That would result in myint == 9800.

I think he may have meant [tt]int myint = (int)(myfloat * 100);[/tt] so that the multiplication would process before the casting.

It would automatically be cast to int because he is multiplying by an int and storing as an int.  A typecast is not needed.