| Author | Message | Time |
|---|---|---|
| UserLoser | 1. Key in the first three digits of your phone number (NOT the area code) 2. Multiply by 80 3. Add 1 4. Multiply by 250 5. Add the last 4 digits of your phone number 6. Add the last 4 digits of your phone number again 7. Subtract 250 8. Divide number by 2 | February 1, 2006, 3:43 AM |
| Explicit[nK] | It is cool. :) | February 1, 2006, 3:51 AM |
| Topaz | ...It goes in a mathematical loop. | February 1, 2006, 4:34 AM |
| inner. | Eh, it is "kinda" cool, waste of my time but bleh. ;) | February 1, 2006, 4:40 AM |
| kamakazie | Let x == first 3 digits of your phone number Let y == last 4 digits of your phone number ((x*80+1)*250+y+y-250)/2 (20000*x+250+2y-250)/2 10000*x+y xxxyyyy | February 1, 2006, 4:43 AM |
| hismajesty | pretty cool. | February 1, 2006, 9:59 PM |
| Yoni | Ass-crapfully lame. | February 3, 2006, 10:44 AM |
| JoeTheOdd | Weak. | February 6, 2006, 2:57 AM |
| inner. | Got it from Ebaumsworld, eh? | February 6, 2006, 10:14 PM |