| Author | Message | Time |
|---|---|---|
| I_Smell_Tuna | If the third and fourth bytes are supposed to be for the destination port how do you split up the port number between those two bytes? | February 15, 2005, 3:33 AM |
| shout | Very carefully with alot of practice. You need to convert the value to a byte array, then stick it in. Converting it depends on your langauge. | February 15, 2005, 3:37 AM |
| I_Smell_Tuna | Visual Basic | February 15, 2005, 3:41 AM |
| tA-Kane | A method that a lot of beginning Visual Basic users use is to convert the port (an integer) to a hexadecimal value using the Hex() function, then use Val() for each byte (meaning twice), using a different part of the result from Hex(). [code]Dim Result As String // the result goes into here, to be written to the network stream Dim HexStr As String // temporary buffer for hexadecimal string Dim Port As Integer // the port you want to write to the network stream Port = 6112 HexStr = Right("000" & Hex(Port), 4) Result = Val("&h" & Left(HexStr, 2)) & Val("&h" & Right(HexStr, 2))[/code] Note that this does not consider endianness, which may be incorrect for most Visual Basic implementations trying to make use of the SOCKS protocol. | February 15, 2005, 8:39 AM |
| NetNX | endianness? explain... | February 18, 2005, 3:27 PM |
| tA-Kane | 0x0001 is 1 on one platform, whereas it's 65536 on another platform. | February 19, 2005, 12:45 AM |
| Kp | No, it isn't. ;) 65536 = 2**16 = 0x10000. You forgot a zero. :) | February 19, 2005, 2:17 AM |
| tA-Kane | Oh well, I was slightly distracted when I posted that. Here's the corrected statement: [quote author=tA-Kane link=topic=10565.msg100467#msg100467 date=1108773907]0x0001 is 1 on one platform, whereas it's 256 on another platform.[/quote] | February 19, 2005, 9:09 AM |