Author | Message | Time |
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Brandon | I am trying to do some PreCalc homework and I am having problems.. I don't know why, maybe it is just to easy for me to get.. But anyways, here is the problem: Instructions: Find a number t such that the line passing through the two given points has slope -2. Problem: (t + 1,5); (6, -3t + 7) I am really confused, what do I do? | January 12, 2005, 10:49 PM |
kamakazie | [quote author=Brandon link=topic=10175.msg95017#msg95017 date=1105570175] I am trying to do some PreCalc homework and I am having problems.. I don't know why, maybe it is just to easy for me to get.. But anyways, here is the problem: Instructions: Find a number t such that the line passing through the two given points has slope -2. Problem: (t + 1,5); (6, -3t + 7) I am really confused, what do I do? [/quote] Well, the equation for the slope between two points (x1, y1) and (x2, y2) is Rise/Run or (y2 - y1) / (x2 - x1) = m. So, you have the slope, the two points. Now you can plugin the values and solve for t using simple algebra. | January 12, 2005, 11:41 PM |
Brandon | Omfg, thanks for pointing out the obvious. Haha, I'm sorry, I must be having a bad math day. Thanks! | January 12, 2005, 11:48 PM |